# 4 Evolutionary Game Theory

## 4.1 Game theory

We briefly introduce the study of mathematical models of games, and their relations to the GLV model. While the origin of game theory can be traced back to the 1700s, modern game theory started with von Neumann’s paper On the Theory of Games of Strategy, published in 1928, and with the subsequent 1944 book with Morgensten Theory of Games and Economic Behavior. John Nash’s paper (Nash 1950) introduced the notion of a Nash Equilibrium (NE). Originally, game theory was studied by economists and mathematicians, but with the 1973 book Evolution and the Theory of Games (Maynard Smith 1982), John Maynard Smith showed how the same tools could be used to study evolutionary dynamics, introducing the influential concept of an Evolutionary Stable Strategy (ESS). Evolutionary game theory was greatly advanced through the introduction of the Replicator Equation (RE), which, as we will see later, has strong connection with the GLV model. For a detailaed introduction to evolutionary game theory see Hofbauer and Sigmund (1998).

## 4.2 Two-player matrix games

We start by anayzing games in which two players face each other, each choosing one strategy out of a set. Importantly, we consider static games in which each player makes their decision without having knowledge of the decision of the other player. Player 1 chooses a “pure” strategy $$s_1$$ from the set of pure strategies $$S_1$$, while player 2 chooses $$s_2 \in S_2$$. We call $$\pi_k (s_1, s_2)$$ the payoff for player $$k$$ when player 1 chooses $$s_1$$ and player 2 $$s_2$$. In a matrix game, we can arrange the payoffs for each player in a matrix. We call $$A$$ the matrix of payoffs for player one and $$B$$ that for player two.

### 4.2.1 Example: the prisoner’s dilemma

Two prisoners alleggedly committed a crime, but the police do not have enough evidence to convict them. They therefore approach each prisoner separately, proposing a deal: if the prisoner confesses (“defect” the other prisoner), then their sentence will be reduced. In particular: i) if both confess (both “defect”), they are sentenced to 4 years in prison; ii) if one confesses (“defect”) and the other keeps quiet (“cooperate” with the other prisoner), then the one who has confessed is let free, and the other sentenced to 5 years; iii) if both keep quiet (“cooperate”), then they are both sentenced to two years of detention for some accessory crime.

In matrix form, we have (rows for pl 1 strategy C/D; cols for pl 2 strategy):

$A = \begin{pmatrix} -2 & -5\\ 0 & -4 \end{pmatrix} \quad B = \begin{pmatrix} -2 & -5\\ 0 & -4 \end{pmatrix}$

What is the best strategy player 1 can play—without knowing whether player 2 will confess or not? If player 2 were to keep quiet, player 1 should confess and be let free; if player 2 confesses, on the other hand, player 1 should also confess and get a reduced sentence. As such, each player would rationally choose to confess, thereby getting sentenced to four years in prison; note that if they could trust the other player, they could cooperate to get a much reduced sentence.

The defect/defect is called a Nash Equilibrium: no player can improve their payoff by changing only their own strategy.

## 4.3 Mixed strategies

Above, the player could choose one out of two strategies. A generalization of this situation is one in which players play mixed strategies, i.e., play a given strategy at random according to a set of probabilities. Call $$x_i$$ the probability that player 1 plays strategy $$i$$; then $$\sum_i x_i = 1$$. Similarly, $$y_i$$ is the probability that player 2 plays strategy $$i$$. A natural choice for the payoff of player 1 is therefore:

$\sum_{i=1}^m \sum_{j = 1}^n x_i y_j \pi_1 (s_1, s_2) = x^t A y$ Similarly, we have $$y^t B x$$ for player 2.

A mixed strategy $$x$$ is dominated by mixed strategy $$\tilde{x}$$ if $$\tilde{x}^t A y \geq x A y$$ for every $$y$$. The condition can be written as $$(\tilde{x}^t - x) A y \geq 0$$.

## 4.4 Nash Equilibria

A pair of mixed strategies $$\tilde{x}$$ and $$\tilde{y}$$ is called a Nash Equilibrium for a two person matrix game if:

\begin{aligned} \tilde{x}^t A \tilde{y} \geq x^t A \tilde{y} &\quad \text{for all } x\\ \tilde{y}^t B \tilde{x} \geq y^t B \tilde{x} &\quad \text{for all } y \end{aligned}

Nash proved that every two-person game has at least one Nash Equilibrium.

## 4.5 Evolutionary stable strategies

In the context of evolution, one can consider $$x$$ to be the proportion of individuals (e.g., of different species, or phenotypes) displaying different characteristics. When playing against each other, they win or lose, and their payoffs are invested in reproduction. Because the different “strategies” (populations, phenotypes) play against each other, the payoff matrix is the same for all players, and encoded in matrix $$A$$.

In this context, a strategy $$x$$ is called an evolutionary stable strategy if two conditions are met: $x^t A x \geq y^t A x \quad \text{for all } y$ meaning that $$x$$ plays against itself not worse than any other strategy, and

$\text{If } y \neq x \text{ then } y^t A x = x^t A x \text{ implies } x^t A y > y^t A y$

meaning that if $$y$$ plays as well as $$x$$ against $$x$$, then $$x$$ plays against $$y$$ better than $$y$$ against itself.

We next connect NE and ESS with dynamical systems.

## 4.6 Replicator dynamics

The replicator equation for this type of games can be written as:

$\dfrac{d x_i}{dt} = x_i \left( \sum_j A_{ij} x_j - \sum_{jk} x_j A_{jk} x_k \right)$

If we define $$f = A x$$ as a vector reporting the “fitness”" of each population at time $$t$$, and $$\bar{f} = \sum_{jk} x_j A_{jk} x_k = x^t A t$$ as the average fitness at time $$t$$ we can write the replicator equation more compactly as:

$\dfrac{d x_i}{dt} = x_i (f_i - \bar{f})$

The RE is essentially equivalent to a GLV model in which we track frequencies instead of abundances.

Importantly, we can see $$x$$ as a “mixed strategy” for the symmetric game encoded in $$A$$. In this context, an equilibrium of the replicator equation is a Nash Equilibrium for the game; similarly, a stable equilibrium for the replicator equation is an Evolutionary Stable Strategy.

### 4.6.1 Invariants

Adding a constant to each column of $$A$$ does not alter the dynamics. We have $$B = A + e b^t$$, where $$e$$ is a vector of ones. Then:

\begin{aligned} x_i \left( \sum_j B_{ij} x_j - \sum_{kj} x_k B_{kj} x_j \right) & = x_i \left( \sum_j (A_{ij} + b_j) x_j - \sum_{kj} x_k (A_{kj} + b_j) x_j \right)\\ &= x_i \left(\sum_j A_{ij} x_j + \sum_j b_j x_j - \sum_{kj} x_k A_{kj} x_j - \sum_{kj} x_k b_{j} x_j \right)\\ &= x_i \left(\sum_j A_{ij} x_j + \sum_j b_j x_j - \sum_{kj} x_k A_{kj} x_j - \sum_{j} b_{j} x_j \right)\\ &= x_i \left(\sum_j A_{ij} x_j - \sum_{kj} x_k A_{kj} x_j \right)\\ \end{aligned}

Similarly, multiplying each column of $$A$$ by a (possibly different) positive constant does not alter dynamics (it just rescales time). As such, if $$A_2 = A_1 D + eb^t$$ the replicator equations formed using $$A_1$$ and $$A_2$$ are equivalent.

### 4.6.2 Rock-paper-scissor

Let’s try our hand with a simple zero-sum (i.e., $$A = -A^t$$) replicator equation. We have three populations (“rock”, “paper”, and “scissors”) with payoff matrix:

$A = \begin{pmatrix} 0 & -1 & 1\\ 1 & 0 & -1\\ -1 & 1 & 0 \end{pmatrix}$

We start the population at a random initial condition, and track dynamics:

library(deSolve) # integrate ODEs
library(tidyverse) # plotting and wrangling
# define the differential equation
RE <-function(t, x, parameters){
with(as.list(c(x, parameters)), {
x[x < 10^-8] <- 0 # prevent numerical problems
x <- x / sum(x) # keep on simplex
dxdt <- x * (A %*% x - sum(x * A %*% x))
list(dxdt)
})
}
# function to plot output
plot_ODE_output <- function(out){
out <- as.data.frame(out)
colnames(out) <- c("time", paste("sp", 1:(ncol(out) -1), sep = "_"))
out <- as_tibble(out) %>% gather(species, density, -time)
pl <- ggplot(data = out) +
aes(x = time, y = density, colour = species) +
geom_line()
show(pl)
return(out)
}
# general function to integrate RE
integrate_RE <- function(A, x0, maxtime = 40, steptime = 0.05){
times <- seq(0, maxtime, by = steptime)
parameters <- list(A = A)
# solve numerically
out <- ode(y = x0, times = times,
func = RE, parms = parameters,
method = "ode45")
# plot and make into tidy form
out <- plot_ODE_output(out)
return(out)
}
# payoff matrix
A <- matrix(c(0, -1, 1,
1, 0, -1,
-1, 1, 0), 3, 3, byrow = TRUE)
# initial conditions
x0 <- runif(3)
x0 <- x0 / sum(x0)
rps <- integrate_RE(A, x0) What if we start all populations at the same density?

x0 <- rep(1 / 3, 3)
rps <- integrate_RE(A, x0) And if they are close to the 1/3?

x0 <- rep(1/3, 3) + 0.05 * runif(3)
x0 <- x0 / sum(x0)
rps <- integrate_RE(A, x0) ### 4.6.3 Equivalence with GLV

For a given $$n-$$species GLV system, there is an equivalent $$(n+1)-$$dimensional replicator equation with zeros in the last row of the matrix. To show this, let’s take our functions for integrating GLV:

# Generalized Lotka-Volterra model
GLV <- function(t, x, parameters){
with(as.list(c(x, parameters)), {
x[x < 10^-8] <- 0 # prevent numerical problems
dxdt <- x * (r + A %*% x)
list(dxdt)
})
}
# general function to integrate GLV
integrate_GLV <- function(r, A, x0, maxtime = 100, steptime = 0.5){
times <- seq(0, maxtime, by = steptime)
parameters <- list(r = r, A = A)
# solve numerically
out <- ode(y = x0, times = times,
func = GLV, parms = parameters,
method = "ode45")
# plot and make into tidy form
out <- plot_ODE_output(out)
return(out)
}

And integrate the simple system:

r <- c(1, 2, 3)
A <- matrix(c(-1, 0.5, 0.1,
-0.7, -2, 0,
-0.3, 0, -5), 3, 3, byrow = TRUE)
x0 <- c(0.1, 3, 1)
glvex <- integrate_GLV(r, A, x0) B <- matrix(0, 4, 4)
B[1:3, 1:3] <- A
B[1:3, 4] <- r
B
y0 <- c(x0, 1)
y0 <- y0 / sum(y0)
reex <- integrate_RE(B, y0) #      [,1] [,2] [,3] [,4]
# [1,] -1.0  0.5  0.1    1
# [2,] -0.7 -2.0  0.0    2
# [3,] -0.3  0.0 -5.0    3
# [4,]  0.0  0.0  0.0    0

Now let’s look at the equilibrium of the GLV model:

glvex %>% filter(time == 100)
# # A tibble: 3 x 3
#    time species density
#   <dbl> <chr>     <dbl>
# 1   100 sp_1      1.32
# 2   100 sp_2      0.538
# 3   100 sp_3      0.521

And recover it from the RE equation (just divide by the density of the extra “species”):

reex %>% filter(time == 40)
reex %>% filter(time == 40) %>% mutate(density = density / tail(density, 1))
# # A tibble: 4 x 3
#    time species density
#   <dbl> <chr>     <dbl>
# 1    40 sp_1      0.391
# 2    40 sp_2      0.159
# 3    40 sp_3      0.154
# 4    40 sp_4      0.296
# # A tibble: 4 x 3
#    time species density
#   <dbl> <chr>     <dbl>
# 1    40 sp_1      1.32
# 2    40 sp_2      0.538
# 3    40 sp_3      0.521
# 4    40 sp_4      1

Not only the equilibria are the same, but also the dynamics are the same once time has been properly rescaled. Similarly, for each RE system we can always recover a matrix with zero in the last row by applying the transformations detailed above, and therefore recover the corresponding GLV. For example, take the matrix for the RPS above, and make each coefficient in the last row zero by adding the appropriate constant to each column. Then one recovers some sort of a predator-prey system:

r <- c(-1, 1)
A <- matrix(c(-1, 2,
-2, 1), 2, 2, byrow = TRUE)
x0 <- c(0.9, 1.1)
glvex <- integrate_GLV(r, A, x0, maxtime = 15, steptime = 0.01) in which the species oscillate around one.

### 4.6.4 Hypertournament games

The rock-paper-scissor game above is a simple case of a “hypertournament” game. Take the zero-sum payoff matrix $$A = -A^t$$. Then, we have

$\sum_i \sum_j A_{ij} x_i x_j = 0$ and the RE simplifies to

$\dfrac{d x}{dt} = D(x) A x$

At equilibrium, either some elements of $$x$$ are zero, or

$A x^\star = 0$ meaning that if a feasible equilibrium $$x^\star$$ exists, it is an eigenvector of $$A$$ corresponding to a zero eigenvalue.

#### 4.6.4.1 Number of coexisting species

We now show how the equations above can arise when modeling ecological dynamics. Suppose that a forest is composed of a fixed number of trees. Each time a tree dies (with rate $$d = 1$$ for all species), a gap in the canopy opens, and species will compete to colonize it. Let’s assume that two seeds (sampled with probability proportional to the density of the species) land in the empty patch, and that they compete to fill the gap. Call $$H_{ij}$$ the probability that $$i$$ wins when competing with $$j$$; we have $$H_{ij} + H_{ji} = 1$$. We can write the dynamics (Grilli et al. 2017) as:

\begin{aligned} \dfrac{d x}{dt} &= x_i \left(\sum_j 2 H_{ij} x_j - 1 \right) \\ &=x_i \sum_j (2 H_{ij} x_j - x_j) \\ &= x_i \sum_j (H_{ij} x_j + (1 - H_{ji}) x_j - x_j) \\ &= x_i \sum_j (H_{ij} - H_{ji}) x_j \\ &= x_i \sum_j A_{ij} x_j \end{aligned}

I.e., we recover the RE for a zero-sum game. What happens if we draw $$H$$ (and therefore $$A$$) at random? Allesina and Levine (2011) and Grilli et al. (2017) applied the results of Fisher and Reeves (1995) and Brandl (2017) to show that, when $$n$$ species compete, the probability of observing $$k$$ coexisting is $$p(k|n) = \binom{n}{k} 2^{1-n}$$ when $$k$$ is odd, and $$p(k|n) = 0$$ when $$k$$ is even.

Importantly, to find the set of coexisting species we do not need to integrate dynamics. One can use linear programming to solve for the set of species that will coexist.

library(lpSolve)
# Build a random matrix H such that H_ij + H_ji = 1
random_H <- function(n){
# build random hypertournament H
H <- matrix(runif(n * n), n, n)
return(H / (H + t(H)))
}
# Find the optimal strategy for the two-person game encoded in H
# using linear programming.
# This is also the coexistence equilibrium of the dynamical system.
find_optimal_strategy <- function(H){
n <- dim(H)
f.obj <- rep(1, n)
f.con <- H
f.rhs <- rep(1, n)
f.dir <- rep("<=", n)
z <- lp ("max", f.obj, f.con, f.dir, f.rhs)
return(z$solution / sum(z$solution))
}

Now let’s try to count how many species suvive when starting with 10:

n <- 10
num_simulations <- 5000
results <- tibble(simulation = 1:num_simulations, coexisting = 0)
for (i in 1:num_simulations){
H <- random_H(n)
coexisting <- find_optimal_strategy(H)
results[i,"coexisting"] <- sum((coexisting > 0)*1)
}
# and plot
ggplot(data = results) +
aes(x = coexisting) +
geom_bar() +
scale_x_continuous(breaks = 0:10) ### 4.6.5 Lyapunov function

In the rock-paper-scissor example above, species cycled neutrally around the unique equilibrium point. To show that this is in fact the behavior of this type of RE, we write a Lyapunov function. By finding a constant of motion we can show that the species will follow closed orbits.

Suppose $$x_{i}^\star > 0$$ is the equilibrium for the system. We write:

$V(x) = -\sum_i x_i^\star \log \frac{x_i}{x_i^\star} .$

Because of Gibbs’ inequality, $$V(x) \geq 0$$ for any $$x$$, and is equal to zero only if $$x = x^\star$$. Note also that at equilibrium $$2 \sum_j H_{ij} x_j^\star = 1$$. We write:

\begin{aligned} \dfrac{d V}{d t} &= \sum_i \dfrac{\partial V}{\partial x_i} \dfrac{d x_i}{d t}\\ &= - \sum_i \frac{x_i^\star}{x_i} \dfrac{d x_i}{d t} \\ &= -2 \sum_{i,j} x_i^\star H_{ij}x_j + \sum_i x_i^\star\\ &= -2 \sum_{i,j} x_i^\star H_{ij}x_j + 1\\ &= \sum_j \left(-2 \sum_i H_{ij}x_i^\star \right) x_j + 1\\ &= \sum_j \left(-2 \sum_i (1 - H_{ji}) x_i^\star \right) x_j + 1\\ &= \sum_j \left(-2 \sum_i x_i^\star + 2 \sum_i H_{ji} x_i^\star \right) x_j + 1 \\ &= \sum_j \left(-2 + 1 \right) x_j + 1 \\ &=- \sum_j x_j + 1\\ &= 0 \end{aligned}

We have found a constant of motion, meaning that the system will follow closed orbits. Hence, unless we start the system precisely at $$x^\star$$, the abundances will cycle neutrally around the equilibrium.

Let’s try with a larger system:

n <- 5
# search for random H yielding all species coexisting
i <- 0
while(TRUE){
i <- i + 1
set.seed(i)
H <- random_H(n)
x_star <- find_optimal_strategy(H)
if (all(x_star) > 0) break
}
# payoff matrix
A <- H - t(H)
# initial conditions close to equilibrium
x0 <- x_star + runif(n) * 0.2
x0 <- x0 / sum(x0)
fivespp <- integrate_RE(A, x0, maxtime = 400, steptime = 0.1) ### 4.6.6 Higher-order interactions

We can extend the game above to the case in which three (or more) seeds compete to fill each patch. Grilli et al. (2017) showed that in this case, one can write the replicator equation:

$\dfrac{d x_i}{dt} = x_i \sum_{j,k} A_{ijk} x_j x_k$ where the tensor $$A$$ (a three-dimensional matrix) encodes the effect of a pair of species ($$j$$ and $$k$$) on the density of $$i$$. Importantly, one can choose the tensor such that the equilibrium is the same as for the two-player replicator equation: take $$A_{ijk} = 2 H_{ij} H_{ik} - H_{ji} H_{jk} - H_{ki} H_{kj}$$, which can be derived from first principles by writing the stochastic dynamics. What is surprising is that, while the equilibrium is unchanged, the dynamics are now globally stable:

# Now payoff is a tensor
RE_3 <- function(t, x, parameters){
with(as.list(c(x, parameters)), {
x[x < 10^-8] <- 0 # prevent numerical problems
x <- x / sum(x) # keep on simplex
n <- length(x)
dxidt <- rep(0, n)
for (i in 1:n){
dxidt[i] <- x[i] * x %*% P3[i,,] %*% x
}
list(dxidt)
})
}
# general function to integrate RE_3
integrate_RE_3 <- function(H, x0, maxtime = 40, steptime = 0.05){
times <- seq(0, maxtime, by = steptime)
n <- nrow(H)
P3 <- array(0, c(n, n, n))
for (i in 1:n){
for (j in 1:n){
for (k in 1:n){
P3[i,j,k] <- 2 * H[i,j] * H[i,k] -  H[j,i] * H[j,k] - H[k,i] * H[k,j]
}
}
}
parameters <- list(P3 = P3)
# solve numerically
out <- ode(y = x0, times = times,
func = RE_3, parms = parameters,
method = "ode45")
# plot and make into tidy form
out <- plot_ODE_output(out)
return(out)
}
# integrate the system above
fivespp <- integrate_RE_3(H, x0, maxtime = 800, steptime = 0.1) And the rock-paper-scissors:

H <- matrix(c(1/2, 1, 0,
0, 1/2, 1,
1, 0, 1/2), 3, 3, byrow = TRUE)
x0 <- runif(3)
x0 <- x0 / sum(x0)
rps <- integrate_RE_3(H, x0, maxtime = 50, steptime = 0.1) ### References

Allesina, Stefano, and Jonathan M Levine. 2011. “A Competitive Network Theory of Species Diversity.” Proceedings of the National Academy of Sciences 108 (14): 5638–42.

Brandl, Florian. 2017. “The Distribution of Optimal Strategies in Symmetric Zero-Sum Games.” Games and Economic Behavior 104: 674–80.

Fisher, David C, and Richard B Reeves. 1995. “Optimal Strategies for Random Tournament Games.” Linear Algebra and Its Applications 217: 83–85.

Grilli, Jacopo, György Barabás, Matthew J Michalska-Smith, and Stefano Allesina. 2017. “Higher-Order Interactions Stabilize Dynamics in Competitive Network Models.” Nature 548 (7666): 210.

Hofbauer, Josef, and Karl Sigmund. 1998. Evolutionary Games and Population Dynamics. Cambridge university press.

Maynard Smith, John. 1982. Evolution and the Theory of Games. Cambridge university press.

Nash, John F. 1950. “Equilibrium Points in N-Person Games.” Proceedings of the National Academy of Sciences 36 (1): 48–49.